X^2+16x-1728=0

Solution for X^2+16x-1728=0 equation:

X^2+16X-1728=0

a = 1; b = 16; c = -1728;
Δ = b2-4ac
Δ = 162-4·1·(-1728)
Δ = 7168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7168}=\sqrt{1024*7}=\sqrt{1024}*\sqrt{7}=32\sqrt{7}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32\sqrt{7}}{2*1}=\frac{-16-32\sqrt{7}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32\sqrt{7}}{2*1}=\frac{-16+32\sqrt{7}}{2}
$